When parallel lines are cut by transversals, the lengths of the segments of the transversals are proportional.
6/4 = 5/x
6x = 5 * 4
6x = 20
x = 20/6 = 10/3
x = 3 1/3
Answer: B. 3 1/3
In the figure we have three parallel lines cut by two transversals
The theorem stares:
If two or more parallel lines are cut by two transversals, then they divide the transversals proportionally.
Applying this theorem we have:
[tex] \frac{4}{x} =\frac{6}{5} [/tex]
To solve for x we cross multiply
6x=20
Dividing both sides by 6 we have:
[tex] x=\frac{20}{6} =\frac{10}{3} =3\frac{1}{3} [/tex]
The second option x=[tex] 3\frac{1}{3} [/tex] is the right answer