Respuesta :

When parallel lines are cut by transversals, the lengths of the segments of the transversals are proportional.

6/4 = 5/x

6x = 5 * 4

6x = 20

x = 20/6 = 10/3

x = 3 1/3

Answer: B. 3 1/3

In the figure we have three parallel lines cut by two transversals

The theorem stares:

If two or more parallel lines are cut by two transversals, then they divide the transversals proportionally.

Applying this theorem we have:

[tex] \frac{4}{x} =\frac{6}{5} [/tex]

To solve for x we cross multiply

6x=20

Dividing both sides by 6 we have:

[tex] x=\frac{20}{6} =\frac{10}{3} =3\frac{1}{3} [/tex]

The second option x=[tex] 3\frac{1}{3} [/tex] is the right answer