Question

let logb (2)= 2.212 and logb(3)=3.415 find log 24

Answer 1

we are given

logb (2)= 2.212

logb(3)=3.415

we can use log formula

$log(24)=log(8*3)$

$log(24)=log(8)+log(3)$

$log(24)=log(2^3)+log(3)$

$log(24)=3log(2)+log(3)$

now, we can plug values

$log(24)=3*2.212+3.415$

$log(24)=10.051$................Answer