Question

Particle with a mass of 1.7 × 10-20 kg is oscillating with simple harmonic motion with a period of 3.4 × 10-5 s and a maximum speed of 2.6 × 103 m/s. calculate (a) the angular frequency and (b) the maximum displacement of the particle.

Answer 1

(a) angular frequency= ω=184706 rad/s

Explanation:

angular frequency= ω= 2π/T

T= time period= 3.4 x 10⁻⁵ s

ω= 2π/ (3.4 x 10⁻⁵)

ω=184706 rad/s

(b) maximum displacement of the particle= a=0.0141 m

Explanation:

maximum velocity is given by Vmax= aω

a= amplitude of maximum displacement

ω= angular frequency

2.6 x 10³= a (184706)

a=0.0141 m