Respuesta :

Since, the angle between the machine and angle of press is [tex] 60^{\circ} [/tex] as shown in the attached image.

Therefore, the actual weight lifted by the power lifter is given by [tex] w \times \cos \Theta [/tex]

where 'w' stands for the weight being lifted and [tex] \Theta [/tex] is the angle of press.

Now,

actual weight lifted by the power lifter = [tex] 720 \times \cos 60^{\circ} [/tex]

= [tex] 720 \times \frac{1}{2} = 360 [/tex] pounds.

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