Question

An electron moves across earth's equator at a speed of 2.5 ???? 106 m/s and in a direction 35° n of
e. at this point, earth's magnetic field has a direction due north, is parallel to the surface, and has a magnitude of 0.10 ???? 10????4 t. what is the force acting on the elec- tron due to its interaction with earth's magnetic field?

Answer 1

The force acting on the electron is 0.57*10^(-17) N.

The force on the electron is calculated by the Lauren law.

F=BQvsinθ

F=0.10*〖10〗^(-4)*1.6*〖10〗^(-19)*2.5*10^(6)sin35°

=0.57*10^(-17) N

Therefore the force on the electron is 0.57*10^(-17) N