Question

A 76 ​-ton monolith is transported on a causeway that is 2500 feet long and has a slope of about 3.4 degrees. how much force parallel to the incline would be required to hold the monolith on this​ causeway?

Answer 1

We can say that the force required to hold the monolith is same as the component of weight along the inclined plane

$F = mgsin\theta$

here we have

m =76 ton = 68946 kg

$\theta = 3.4 degree$

now force required to hold this

$F = mgsin\theta$

$F = 68946*9.8*sin3.4$

$F = 40071.6 N$