Let initially number of fishes =x
He gives 2/3 of his fish to a local high school, that is he gives 2x/3 fish .
So number of fishes left = x -(2x/3) = x/3 . And he gives 2/5 of x/3 to an elementary school , that is , he gives 2x/15 fishes to the elementary school. And finally the number of fishes left =30 , that is
[tex] x-(\frac{2x}{3}+\frac{2x}{15})=30 [/tex]
[tex] x-\frac{12x}{15}=30 [/tex]
[tex] \frac{3x}{15}=30 [/tex]
[tex] x = 150 [/tex]
So initially he have 150 fishes .