Question

What is the rate of increase for the function f(x)=1/3(3sqr24)^2x

A.1/3

B.2 3sqr3

C.4

D. 4 3sqr9

Answer 1

Answer:

The correct option is D.

Step-by-step explanation:

The general form of exponential function is

$f(x)=ab^x$             ... (1)

Where a is initial value and b is rate of increase.

The given function is

$f(x)=\frac{1}{3}(\sqrt[3]{24})^{2x}$

$f(x)=\frac{1}{3}(\sqrt[3]{2^3\cdot 3})^{2x}$

$f(x)=\frac{1}{3}(2\sqrt[3]{3})^{2x}$

$f(x)=\frac{1}{3}((2\sqrt[3]{3})^2)^{x}$

$f(x)=\frac{1}{3}(4\sqrt[3]{3^2})^{x}$

$f(x)=\frac{1}{3}(4\sqrt[3]{9})^{x}$         .... (2)

From (1) and (2), we get

$b=4\sqrt[3]{9}$

Therefore the correct option is D.

Answer 2

Answer:

D

Step-by-step explanation:

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