Which one? And show work

we are given
[tex] (8x^4-128) [/tex]
Firstly , we can factor out 8
[tex] 8(x^4-16) [/tex]
now, we can rewrite it
[tex] 8(x^4-(2)^4) [/tex]
now, we can use formula
[tex] (a^4-b^4)=(a^2+b^2)(a-b)(a+b) [/tex]
so, we will get
[tex] 8(x^4-(2)^4)=8(x^2+4)(x-2)(x+2) [/tex].............Answer