Question

The rectangular plates in a parallel-plate capacitor are 0.063 m × 5.4 m. A distance of 3.5 × 10–5 m separates the plates. The plates are separated by a dielectric made of Teflon, which has a dielectric constant of 2.1. What is the capacitance of the capacitor?

Answer: .18

Answer 1

the capacitance of the capacitor= C=0.18 μ F

Explanation:

The capacitance of a parallel plate capacitor is given by

$C= \frac{ K\epsilon a}{d}$

K= dielectric constant=2.1

ε= 8.85 x 10⁻¹² C²/Nm²

a= area of plates=0.063 x 5.5= 0.302 m²

d= distance between the plates= 3.5 x 10⁻⁵m

C= (2.1)(8.85 x 10⁻¹²)(0.302)/ (3.5 x 10⁻⁵)

C=1.8 x 10⁻⁷F

C=0.18 μ F

Answer 2

Answer:

0.18

Explanation: correct on edge