[tex] x^2-y^2=2\\\underline{x^2+y^2=4}\\\\2x^2=6\\x^2=3\\x=-\sqrt3 \vee x=\sqrt3\\\\3+y^2=4\\y^2=1\\y=-1 \vee y=1\\\\x\in\{(-\sqrt3,-1),(-\sqrt3,1),(\sqrt3,-1),(\sqrt3,1)\} [/tex]
So, there are 4 solutions.
