Question

Point X is located at (2,-6), and point Z is located at (0,5). Find the y value for point Y that is located 1/5 the distance from point X to point Z

Answer 1

The y-difference between the points is 5-(-6) = 11. One-fifth of that is 11/5 = 2.2. Adding that to the y-value of point X means ...

... the y-value of point Y is -6+2.2 = -3.8