Equation 1 is [tex] \frac{4}{3}x -\frac{2}{5}y =2 [/tex] ,
Equation 2 is [/tex] 3x-2y = -1 [/tex]
for first equation LCD= 3 *5 = 15 , So we multiply whole equation by 15
[tex] \frac{4}{3} *15x -\frac{2}{5}*15 y =2*15 [/tex]
[tex] 20x - 6y = 30 [/tex]
Now multiply second equation by -3 , to make the coefficient of y equal and opposite , so that we can apply the elimination method
[tex] -9x+6y = 3 [/tex]
Add both the equations
[tex] 20x -9x -6y +6y = 30+3 [/tex]
[tex] 11x= 33 [/tex]
Divide both sides by 11
[tex] x=3 [/tex]
Plug in any one of the equation we get
3(3) -2y = -1
9 - 2y = -1
subtract 9 from both sides
-2y = -10
divide both sides by -2
y=5
So the solution is x= 3 , y= 5
Which means
a. The system is consistent and independent. TRUE