Respuesta :
we are given
Let's assume initial population in 2006
initial population 12000
[tex] P=12000 [/tex]
[tex] r=0.05 [/tex]
[tex] t=2020-2006 [/tex]
[tex] t=14 [/tex]
now, we can use formula
[tex] A=Pe^{rt} [/tex]
we can plug values
[tex] A=12000e^{0.05*14} [/tex]
we can solve it
and we get
[tex] A=24165 [/tex].............Answer
Population at any time t is given as:
[tex] P(t)=P(0)(1+r)^t [/tex]
So, P(t)=12000(1+0.05)^t
From, 2006 to 2020, there are 14 years, so t=14
P(14)=12000(1+0.05)^14
=12000(1.05)^14=12000*1.979
=23748
So, Population in 2020,(14 years later)=23748