Question

A square pyramid has sides of 8 m. Each face is an equilateral triangle.

What is the lateral area of the pyramid?

Answer 1

Lateral Area means Area of all four triangles

Now area of 1 triangle = $\frac{\sqrt{3}}{4} a^2 = \frac{\sqrt{3}}{4} 8^2$

= $\frac{\sqrt{3}}{4} * 64 = 16\sqrt{3}$ square meters

Now for four triangles we multiply by 4

So

Lateral area of pyramid =$4* 16\sqrt{3} = 64\sqrt{3}$ m^2

that is Option D

Answer 2

Answer:

I think is the Option D