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Simplify open parentheses x to the 2 ninths power close parentheses to the 3 eighths power.

x to the 5 seventeenths power
x to the 1 twelfth power
x to the 11 over 72 power
x to the 43 over 72 power

Respuesta :

Riia

The given expression is

[tex] (x^{2/9})^{3/8} [/tex]

Here we have two exponents, so we have to use power of a power rule of exponent , in which we need to multiply the exponents . And on doint this, we will get

[tex] x^({2/9}*{3/8}) =x^{6/72} = x^{1/12} [/tex]

And it is equal to x to the 1 twelfth power. SO the correct option is the second option .

Answer:

Option 2

[tex](x^{\frac{2}{9}})^{\frac{3}{8}}=x^{\frac{1}{12}}[/tex]

Step-by-step explanation:

Given : Open parentheses x to the 2 ninths power close parentheses to the 3 eighths power.

To find : Simplify the given expression?

Solution :

Open parentheses x to the 2 ninths power close parentheses to the 3 eighths power i.e, [tex](x^{\frac{2}{9}})^{\frac{3}{8}}[/tex]

Applying the power rule of exponent, [tex](x^a)^b=x^{a\cdot b}[/tex]

[tex](x^{\frac{2}{9}})^{\frac{3}{8}}[/tex]

[tex]=x^{\frac{2}{9}\times\frac{3}{8}}[/tex]

[tex]=x^{\frac{2\times 3}{9\times 8}}[/tex]

[tex]=x^{\frac{6}{72}}[/tex]

[tex]=x^{\frac{1}{12}}[/tex]

Therefore, Option 2 is correct.

[tex](x^{\frac{2}{9}})^{\frac{3}{8}}=x^{\frac{1}{12}}[/tex]

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