Respuesta :
The given expression is
[tex] (x^{2/9})^{3/8} [/tex]
Here we have two exponents, so we have to use power of a power rule of exponent , in which we need to multiply the exponents . And on doint this, we will get
[tex] x^({2/9}*{3/8}) =x^{6/72} = x^{1/12} [/tex]
And it is equal to x to the 1 twelfth power. SO the correct option is the second option .
Answer:
Option 2
[tex](x^{\frac{2}{9}})^{\frac{3}{8}}=x^{\frac{1}{12}}[/tex]
Step-by-step explanation:
Given : Open parentheses x to the 2 ninths power close parentheses to the 3 eighths power.
To find : Simplify the given expression?
Solution :
Open parentheses x to the 2 ninths power close parentheses to the 3 eighths power i.e, [tex](x^{\frac{2}{9}})^{\frac{3}{8}}[/tex]
Applying the power rule of exponent, [tex](x^a)^b=x^{a\cdot b}[/tex]
[tex](x^{\frac{2}{9}})^{\frac{3}{8}}[/tex]
[tex]=x^{\frac{2}{9}\times\frac{3}{8}}[/tex]
[tex]=x^{\frac{2\times 3}{9\times 8}}[/tex]
[tex]=x^{\frac{6}{72}}[/tex]
[tex]=x^{\frac{1}{12}}[/tex]
Therefore, Option 2 is correct.
[tex](x^{\frac{2}{9}})^{\frac{3}{8}}=x^{\frac{1}{12}}[/tex]