Question

Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 6/11 and P(T) = 1/10

Answer 1

We use the following fundamental definition from Probability and Set Theory.

$p(S U T)=P(S)+P(T)-P(S and T)$

$P(S and T) =0 because they are mutually exclusive$

$P(S U T)=6/11+1/10=71/110$