By using the base change formula, which states
[tex] \log _{a}b= \frac{\log b}{\log a} [/tex]
The given equation is [tex] \log _{3}5= \frac{\log 5}{\log 3} [/tex]
By substituting the values of log 5 and log 3.
[tex] = \frac{0.6989}{0.477} [/tex]
= 1.46
