Question

How many moles are contained in a 4.67-l sample of gas at 30 c and 199 kpa?

Answer 1

Using ideal gas equation,

PV=nRT

P=199 kpa

V=4.67 L

T=30+273K= 303K

n= number of moles of gas

R=8.321 L·kPa·K-1·mol-1

So using ideal gas equation,

n=PV/RT

=199*4.67/8.321*303\

=0.37 mol

Answer 2

0.37 mole are contained in a 4.67-1 sample of gas at 30c and 199 kpa.

hope it will help you