Question

98 POINTS!! VERY URGENT!!!
Answer the following questions:

Answer 1

$\frac{3x-2}{x^{2}-2x-3} -\frac{1}{x-3}$

factorising the first denominator

x²-2x-3 = x² -3x+x-3 = (x+1)(x-3)

(a) $\frac{3x-2}{(x+1)(x-3)} - \frac{1}{x-3}$

finding LCD

(b) LCD of (x-3)(x+1) and (x-3) is (x-3)(x+1)

(c)

$\frac{3x-2}{(x-3)(x+1)} -\frac{x+1}{(x-3)(x+1)}$

$\frac{3x-2-(x+1)}{(x-3)(x+1)}$

$\frac{3x-2-x-1}{(x-3)(x+1)}$

$\frac{2x-3}{(x-3)(x+1)}$

Answer 2

factorising the first denominator

x²-2x-3 = x² -3x+x-3 = (x+1)(x-3)

(a)  \frac{3x-2}{(x+1)(x-3)} - \frac{1}{x-3}  

finding LCD

(b) LCD of (x-3)(x+1) and (x-3) is (x-3)(x+1)