So we are given an initial equation of: [tex] y=2x-7 [/tex].
We are told that a new path is going to be perpendicular to this line. So to find a slope that is perpendicular to a line, we take the slope of the known line (in this case 2) and we flip it and change the sign. So since this slope is essentially [tex] \frac{2}{1} [/tex], we are going to flip it to make it [tex] \frac{1}{2} [/tex] and change the sign to make it [tex] -\frac{1}{2} [/tex].
So now we know that the slope of the perpendicular line is [tex] -\frac{1}{2} [/tex], we can start a new equation for this line:
[tex] y=-\frac{1}{2}x+b [/tex]
We are also told that the path will intersect at (-2,-3) - this is a solution to the two lines. So to find b in this new equation, let's plug in the x and y values found in the point:
[tex] -3=-\frac{1}{2}(-2)+b [/tex]
Then solve for b:
[tex] -3=1+b [/tex]
[tex] b=-4 [/tex]
So then we plug in our value for b and leave x and y:
[tex] y=-\frac{1}{2}x-4 [/tex]
So this equation now represents the new path.