Greetings!
The formula for the area of any triangle is as followed:
[tex] A_{triangle}=\frac{bh}{2} [/tex]
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Let Statements:
Let the variable...
→ [tex] b [/tex] represent the length of the base of the triangle
→ [tex] h [/tex] represent the length of the height of the triangle
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Using the information provided from the question, we can substitute its values in place of the variables and solve for the last remaining variable:
[tex]10=\frac{(4)(x+3)}{2} [/tex]
Distribute the parenthesis (The Distributive Property) :
[tex]10=\frac{((4)(x)+(4)(3))}{2} [/tex]
[tex]10=\frac{4x+12}{2} [/tex]
Reduce the fraction to lowest terms:
[tex]10=2x+6[/tex]
Add -6 to both sides of the equation:
[tex](10)+(-6)=(2x+6)+(-6)[/tex]
[tex]4=2x[/tex]
Divide both sides of the equation by 2:
[tex] \frac{4}{2}=\frac{2x}{2} [/tex]
[tex]2=x[/tex]
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The Answer to this Problem is:
[tex] \boxed{x=2} [/tex]
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I hope this helped!
-Benjamin
