The domain becomes the range and vice versa, so the domain is [tex] [-3,\infty) [/tex] and the range is [tex] [6,\infty) [/tex].
Answer:
Domain of the function [tex]f^{-1}(x)[/tex] is [tex][-3,\infty )[/tex] and range of the function is [tex]f^{-1}(x)[/tex] is [tex][6,\infty )[/tex].
Step-by-step explanation:
Consider the provided information.
The domain of the function [tex]f(x)[/tex] is [tex][6,\infty )[/tex].
The range of the function [tex]f(x)[/tex] is [tex][-3,\infty )[/tex].
The range of a function [tex]g(x)[/tex] is the domain of the function [tex]g(x)^{-1}[/tex].
Also, the domain of a function [tex]g(x)[/tex] is the range of the function [tex]g(x)^{-1}[/tex].
Therefore, domain of the function [tex]f^{-1}(x)[/tex] is [tex][-3,\infty )[/tex] and range of the function is [tex]f^{-1}(x)[/tex] is [tex][6,\infty )[/tex].