I’m confused on this one

volume of cone = (1/3)(pi)(r^2)h
r = radius = diameter/2 = 8/2 = 4
h = height = 6
volume = (1/3)(3.14159)(4^2)(6)
volume = 100.53096...
Answer: 100.5 units^3
The volume of a cone is one-third the volume of a cylinder into which the cone would fit, that is: base times height, divided by three: [tex]V=\frac{Bh}{3}[/tex]. Since the base is a circle we have: [tex]V=\pi r^{2}\frac{h}{3} [/tex]. By Cavalieri's Principle this holds even for slanted cones such as this one.
Thus:
[tex]V=\pi r^{2}\frac{h}{3} [/tex]
[tex]V=\pi (\frac{8}{4})^{2}(\frac{6}{3})[/tex]
[tex]V=\pi 4^{2}(2) [/tex]
[tex]V=32\pi [/tex]
[tex]V\approx 100.5units^{3}[/tex]