Question

Evaluate 3x^3y-2/5x^-2y^3 for x=2 and y=3

32/405
160/81
2/5

Answer 1

The given expression is

$\frac{3x^3 y^{-2}}{5x^{-2} y^3}$

Given values of x and y are x=2 and y=3

And on substituting these values, we will get

$\frac{3(2)^3 (3)^{-2}}{5(2)^{-2} (3)^3}$

Here we need to convert negative exponents to positive exponent, and for that we need to flip the term with negative exponent .

$\frac{3*2^3*2^2}{5*3^2*3^3}$

$\frac{2^5}{5*3^4}=\frac{32}{405}$

So the correct option is the first option .