Question

Can someone please help me factorize this one:
$0.01y {}^{2} - \frac{1}{4}$

Answer 1

First let us convert 0.01 into fraction:

$\frac{y^{2}}{100} -\frac{1}{4}$

Now we convert 100 and 4 into perfect squares as follows:

$(\frac{y}{10})^{2}-(\frac{1}{2})^{2}$

Now we use the property of :

$x^{2} -y^{2} =(x+y)(x-y)$

$(\frac{y}{10} +\frac{1}{2} ) (\frac{y}{10} -\frac{1}{2} )$