ANSWER: 31.25%
Explaination:
Suppose (x+y)[tex] (x+y)^{5} [/tex] is the binomial distribution with 5 trials. Given that, probability of exactly two success in five trials of a binomial experiment in which the probability of success is 50%.
So, x = 0.5 and y = 0.5
The term
5C2*x²*y³ representing 2 successes and 3 failures.
Now find the value of this term.
5C2*(0.5)²*(0.5)³ = [tex] \frac{5!}{2!3!} [/tex]*[tex] (0.5)^{5} [/tex]
=10*0.03125
= 31.25%
