Question

identify the vertex of f(x)=
${(x - 5)}^{2} - 3$

Answer 1

The given equation is in what we know as "vertex form".

In this form, the equation enters the order of $f(x) = a(x - h)^2 + k$, where vertex is $(h,k)$.

In this case, we have $(x-5)$ for $(x-h)$and for $k$ we have $-3$. So, the vertex is $(5, -3)$

Answer 2

If the quadratic is written in the form

$y=a(x-h)^{2} +k$

then the vertex is the point (h, k).

So from our equation,

$f(x)=(x-5)^{2} -3$

here on comparing our equation with the vertex form we get ,

h=5 and k=-3

vertex (5,-3)