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Question 17 Unsaved
Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green balls and 2 blue balls. A ball is drawn at random from each urn. What is the probability that both balls are blue?

Question 17 options:

110

251

320

4153

Answer 1

The probability of drawing a blue ball from the first urn is 6/(4 + 6) = 6/10 = 3/5.

The probability of drawing a blue ball from the second urn is 2/(2 + 6) = 2/8 = 1/4.

Since we want to find the probability that both balls from each urn are blue, we multiply our answers: 3/5 * 1/4 = 3/20.

The answer is the fraction 3/20.

Answer 2

The probability of drawing a blue ball from the first urn is 6/(4 + 6) = 6/10 = 3/5.

The probability of drawing a blue ball from the second urn is 2/(2 + 6) = 2/8 = 1/4.

Since we want to find the probability that both balls from each urn are blue, we multiply our answers: 3/5 * 1/4 = 3/20.

The answer is the fraction 3/20.

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