Question

I’m confused on this one

Answer 1

Option A is the answer
Perimeter of the parallelogram =20+24+20+24=88mm
Area of the parallelogram =ab sin theta =415.7mm sq...

Answer 2

Perimeter 20 + 24 + 20 + 24 = 88 mm

Sixty degrees makes a $30/60/90$ right triangle, sides in ratio $1: \sqrt{3}: 2$ so the height AM is

$AM = 20(\sqrt 3 / 2) = 10 \sqrt{3}$

$\textrm{area} = b h = (24) (10 \sqrt{3}) = 240 \sqrt{3} \approx 417.7$

Choice a