[tex] \frac{1}{x - 10} : \frac{9x}{x^{2} - 9x - 10} = \frac{x^{2} - 9x - 10}{9x(x - 10)} = \frac{(x + 1)(x - 10)}{9x(x - 10)} = \frac{x + 1}{9x} [/tex]
[tex] Answer.C.) \frac{x + 1}{9x} [/tex]
[tex]\textbf{Spymore}[/tex]
