[tex]\cos A = \dfrac{ \textrm{adjacent}}{\textrm{hypotenuse}} = \dfrac{b}{c}[/tex]
[tex]\sin A = \dfrac{ \textrm{opposite}}{\textrm{hypotenuse}} = \dfrac{a}{c}[/tex]
[tex]\sec A = \dfrac{1}{\cos A} = \dfrac{\textrm{hypotenuse}}{ \textrm{adjacent}} = \dfrac{c}{b}[/tex]
Secant Answer: c/b
[tex]\cot B = \tan A = \dfrac{\sin A}{\cos A} = \dfrac{ \textrm{opposite}}{\textrm{adjacent}} = \dfrac{a}{b}[/tex]
Cotangent B Answer: a/b
[tex] \csc A = \dfrac{1}{\sin A} =\dfrac{\textrm{hypotenuse}}{ \textrm{opposite}} = \dfrac{c}{a}[/tex]
Cosecant Answer: c/a
[tex] \tan A = \cot B = \dfrac a b[/tex]
Tangent Answer: a/b