Question

Question 12 Unsaved 3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l) How many grams of Cu would be needed to react with 2.0 mol HNO3? : 1.50 g 47.6 g 95.3 g 63.5

Answer 1

Answer:

47.6 g

Solution:

The balance chemical equation is as follow,

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

According to equation,

8 mol HNO₃ required = 190.63 g of Cu (3 moles)

So,

2 mol HNO₃ will require = X g of Cu

Solving for X,

X = (190.63 g × 2 mol) ÷ 8 mol

X = 47.65 g of Cu

Answer 2

Answer should be 47.6g

Hope this helps!