paigecropsey
paigecropsey paigecropsey
  • 28-07-2018
  • Mathematics
contestada

ALGEBRA 2, PLEASE HELP ME

ALGEBRA 2 PLEASE HELP ME class=

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PunIntended
PunIntended PunIntended
  • 28-07-2018

I believe the answer is cos^2 theta. Sec^2 theta on the right side of the equation is the inverse of Cos^2 theta, so multiplying the two together will get you 1. Cos^2 theta * Tan^2 theta = Sin^2 theta, and Cos^2 theta * 1 = Cos^2 theta. This all leads to the third and last step in the picture above.

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altavistard
altavistard altavistard
  • 28-07-2018

Multiply both sides of the equation in Part I by (cos theta)^2.

This will result in (cos theta)^2 + (sin theta)^2 = 1.

(Recall that (sec theta)*(cos theta) = 1.)

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