Syedsyed Syedsyed

28-07-2018
Mathematics

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28-07-2018

[tex] \dfrac{4x^2+36}{4x}\cdot\dfrac{1}{5x}=\dfrac{4(x^2+9)}{4x\cdot5x}=\dfrac{x^2+9}{5x^2} [/tex]

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