If the radius of circle A is 6 units, calculate the area of the shaded region...

The formula of an area of a triangle:
[tex]A_{\triangle}=\dfrac{base\cdot height}{2}[/tex]
We have:
[tex]\triangle_{FDE}:\ base=height=1\\\triangle_{GDH}:\ base=height=9[/tex]
substitute:
[tex]A_{\triangle_{FDE}}=\dfrac{1\cdot1}{2}=0.5\\\\A_{\triangle_{GDH}}=\dfrac{9\cdot9}{2}=40.5[/tex]
The formula of an area of a circle:
[tex]A_O=\pi r^2[/tex]
We have [tex]r=6[/tex]
Substitute:
[tex]A_O=\pi\cdot6^2=36\pi\approx36\cdot3.14=113.04[/tex]
The area of the shaded region
[tex]A=A_O-(A_{\triangle_{FDE}}+A_{\triangle_{GDH}})\\\\A=113.04-(0.5+40.5)=113.04-41=72.04\ u^2[/tex]