Let the two consecutive integers be [tex] x [/tex] and [tex] x+1 [/tex]. Given that
[tex] x+x+1=-5\\
2x+1=-5\\
x=-3
[/tex]
The consecutive integers are -3,-2.
4 is subtracted from the smaller integer and 2 is added to the smaller integer the resulting integers are [tex] -3-4=-7 [/tex] and [tex] -3=2=-1 [/tex].
The quotient is [tex] \frac{-7}{-1} =7 [/tex]