Question

WILL MARK BRAINLIEST
Graph the first six terms of a sequence where a1 = 3 and d = −10.

Answer 1

Answer should be the first graph.

a1 stands for the first term in the sequence. So your first term must be a positive 3. After that, you just keep subtracting 10

3, -7, -17, -27 , -37, -47

So the first graph represents it perfectly. Most of the other graphs were forgetting the first term of 3.

Answer 2

Answer:

The correct option is 1.

Step-by-step explanation:

It is given that a1 = 3 and d = −10. It means the given sequence is an AP, where the first term is 3 and the common difference d is -10.

The nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

Substitute a=3 and d=-10 to find the nth term of given AP.

$a_n=3+(n-1)(-10)$

Now, substitute the different values of n to find the first six terms of a sequence.

$a_1=3+(1-1)(-10)=3$

$a_2=3+(2-1)(-10)=3+(1)(-10)=3-10=-7$

$a_3=3+(3-1)(-10)=3+(2)(-10)=3-20=-17$

$a_4=3+(4-1)(-10)=3+(3)(-10)=3-30=-27$

$a_5=3+(5-1)(-10)=3+(4)(-10)=3-40=-37$

$a_6=3+(6-1)(-10)=3+(5)(-10)=3-50=-47$

The coordinates of first six terms of a sequence are (1,-3), (2,-7), (3,-17), (4,-27), (5,-37), (6,-47). All these points are defined by graph 1.

Therefore the correct option is 1.