Question

How would u solve these two problems?

Answer 1

45.

For this, replace x in the equation for 4.

$f(4) = 2(4)^2 - 3\\ f(4)=2(16)-3\\ f(4)=32-3\\ f(4)=29$

The answer is 29, or B.

46.

So firstly, we have to find what f(-10) is in the first equation. For this, replace x for -10 and solve.

$f(-10)=-\frac{2}{5}(-10)-2\\ f(-10)=4-2\\ f(-10)=2$

Now that we know that f(-10) = 2, we can substitute that into the second equation and solve for k.

$2+k=5\\ k=3$

In short, the value of k is 3.