johnjphn
johnjphn johnjphn
  • 27-07-2018
  • Mathematics
contestada

Please help me with this!!

Please help me with this class=

Respuesta :

Numenius
Numenius Numenius
  • 01-08-2018

5x+3y=-6 ...(1)

2x-3y=27 ...(2)

We can add equations (1) and (2) to eliminate y . So,

7x+0=21

7x=21

[tex] \frac{7x}{7} =\frac{21}{7} [/tex] Divide each sides by 21 to isolate x.

So, x= 3

Now plug in x=3 in equation (1) to get the value of y.

So, 5(3)+3y=-6

15 +3y= -6

15+3y-15=-6-15

3y= -21

[tex] \frac{3y}{3} =\frac{-21}{3} [/tex]

So, y=-7.

Hence, x=3 and y=7.

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