Let X be the weekly incomes of a large group of executives. The weekly incomes of a large group of executives follows Normal distribution with mean $2000 and standard deviation $100.
μ =2000, σ =100
We have to find z score for income $2100 i.e x=2100
Z = [tex] \frac{x-mean}{standard deviation} [/tex]
= [tex] \frac{2100 - 2000}{100} [/tex]
Z = 100/100
Z = 1
The z score for income $2100 is 1