Mass of sodium thiosulfate [tex] Na_{2}S_{2}O_{3} [/tex] is 110. g
Volume of the solution is 350. mL
Calculating the moles of sodium thiosulfate:
[tex] 110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}}[/tex] = 0.696 mol[tex] Na_{2}S_{2}O_{3} [/tex]
Converting the volume of solution to L:
[tex] 350. mL * \frac{1 L}{1000 mL} = 0.350 L [/tex]
Finding out the concentration of solution in molarity:
[tex] \frac{0.696 mol}{0.350 L} = 1.99 mol/L [/tex]