Using the rules of exponents
[tex]\left(a^{b}\right)^{c}=a^{(b\cdot c)}\\a^{b}\cdot a^{c}=a^{(b+c)}[/tex]
you can simplify this to
[tex]\left(2^{(2-2)}a^{(-3\cdot 2+5\cdot (-2))}b^{(4\cdot 2+1\cdot (-2))}\right)^-1\\\\=\left(2^{0}a^{-16}b^{6}\right)^{-1}\\\\=\dfrac{a^{16}}{b^{6}}[/tex]
None of these answer choices matches the given expression.