Define x:
Let one of the number be x.
One number = x
The other consecutive number = x + 1
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Form equation:
The product of two consecutive integers is 5 more than their sum.
x(x + 1) = x + ( x+ 1) + 5
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Solve x:
x(x + 1) = x + ( x+ 1) + 5
Distribute x:
x² + x = x + x + 1 + 5
Combine like terms:
x² + x = 2x + 6
Subtract 2x + 6 from both sides:
x² - x - 6 = 0
(x - 3)(x + 2) = 0
x = 3 or x = -2
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Find the two integers:
If x = 3:
One number = x = 3
The other consecutive number = x + 1 = 3 + 1 = 4
If x = -2:
One number = x = -2
The other consecutive number = x + 1 = -2 + 1 = -1
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Answer: The two possible answer is 3 and 4 or -2 and -1
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