The given vector is b= -3i +11j
b=<-3, 11>
here, base= 3(not -3) (this gives an angle in first quadrant the same angle will foam in second quadrant from -ve x-axis)and perpendicular= 11
Now,
tan(θ')= perpendicular/base = 11/3
θ' = tan⁻¹(11/3)
= 74.7448°
but we require the angle from positive x-axis so,
θ = 180-θ'
= 180-74.7448
= 105.255°
B is the correct answer.
