Respuesta :
[tex] \left\{\begin{array}{ccc}y=3x-4\\y=-2x+1\end{array}\right\\\\y=3x-4\\for\ x=0\to y=3(0)-4=-4\to(0;-4)\\for\ x=2\to y=3(2)-4=2\to(2;\ 2)\\\\y=-2x+1\\for\ x=0\to y=-2(0)+1=1\to(0;\ 1)\\for\ x=2\to y=-2(2)+1=-3\to(2;\ -3) [/tex]
Look at the picture.
Answer: x = 1; y = -1 → (1; -1)

The solution of the system of equation is (1, -1).
Given that
The system of the equation;
[tex]\rm y=3x-4\\\\ y=-2x+1[/tex]
We have to determine
The solution of the system of equation.
According to the question
The system of the equation;
[tex]\rm y=3x-4\\\\ y=-2x+1[/tex]
Subtract equation 1 from equation 2
[tex]\rm y - y = 3x-4 - (-2x+1)\\\\0 = 3x-4+2x-1\\\\5x-5=0\\\\5x = 5\\\\x = \dfrac{5}{5}\\\\x = 1[/tex]
Substitute the value of the x in equation 1
[tex]\rm y = 3x-4\\\\y = 3(1) -4\\\\y = 3-4\\\\y = -1[/tex]
Hence, the solution of the system of equation is (1, -1).
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