I don’t know how to start with drawing the diagram for this question.

Consider right triangles ADB and ADC in the figure, right angle D.
By alternate transversals ABD=63° and ACD=11°.
[tex] \tan 63 = \dfrac 8 y[/tex]
[tex] \tan 11 = \dfrac 8{x+y}[/tex]
[tex] y = \dfrac{8}{\tan 63}[/tex]
[tex] x = -y + \dfrac{8}{\tan 11}[/tex]
[tex] x = \dfrac{8}{\tan 11} - \dfrac{8}{\tan 63}[/tex]
[tex] x \approx 37.08 \textrm{ meters}[/tex]
That's in one second, so
Answer: 37 meters per second