breanna3418 breanna3418
  • 26-07-2018
  • Mathematics
contestada

I don’t know how to start with drawing the diagram for this question.

I dont know how to start with drawing the diagram for this question class=

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DeanR
DeanR DeanR
  • 26-07-2018

Consider right triangles ADB and ADC in the figure, right angle D.

By alternate transversals ABD=63° and ACD=11°.

[tex] \tan 63 = \dfrac 8 y[/tex]

[tex] \tan 11 = \dfrac 8{x+y}[/tex]

[tex] y = \dfrac{8}{\tan 63}[/tex]

[tex] x = -y + \dfrac{8}{\tan 11}[/tex]

[tex] x = \dfrac{8}{\tan 11} - \dfrac{8}{\tan 63}[/tex]

[tex] x \approx 37.08 \textrm{ meters}[/tex]

That's in one second, so

Answer: 37 meters per second

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