The equations that represent the points on the table are:
[tex]y - 2= -\frac 16 (x +10)[/tex]
[tex]y - 1= -\frac 16 (x +4)[/tex]
[tex]y - 1= -\frac x6 -\frac 23[/tex]
From the table (see attachment, we have):
[tex](x_1,y_1) = (-10,2)[/tex]
[tex](x_2,y_2) = (-4,1)[/tex]
Calculate the slope (m)
[tex]m = \frac{y_2 - y_1}{x_2 -x_1}[/tex]
So, we have:
[tex]m = \frac{1-2}{-4--10}[/tex]
[tex]m = \frac{-1}{6}[/tex]
[tex]m = -\frac{1}{6}[/tex]
The equation is then calculated as follows:
[tex]y = m(x - x_1) + y_2[/tex]
This gives:
[tex]y = -\frac 16 (x - -10) + 2[/tex]
[tex]y = -\frac 16 (x +10) + 2[/tex]
Subtract 2 from both sides
[tex]y - 2= -\frac 16 (x +10)[/tex] ----- option (B)
Add 1 to both sides
[tex]y - 2 + 1= -\frac 16 (x +10) +1[/tex]
[tex]y - 1= -\frac 16 (x +10) +1[/tex]
Take LCM
[tex]y - 1= -\frac 16 (x +10-6)[/tex]
[tex]y - 1= -\frac 16 (x +4)[/tex] ---- option (C)
Open bracket
[tex]y - 1= -\frac x6 -\frac 46[/tex]
[tex]y - 1= -\frac x6 -\frac 23[/tex] --- option (E)
Hence, the true options are B, C and E
Read more about linear graphs at:
https://brainly.com/question/20106471