Question

Can you help me ? correct me if I'm wrong, thank you !

Answer 1

y=a(x-h)^2+k (vertex form)

where h=-2, and k=-3 (vertex)

so

substituting (-1,-5)

y=a(x+2)-3

solve for a

a=(y+3)/(x+2)

substituting (-1,-5)

=(-5+3)/(-1+2)

=-2/1

=-2

Yes, your answer is correct. Well done.

Answer 2

$\sf Hello!$

• $\sf h = -2$
• $\sf k = -3$
• $\sf x = -1$
• $\sf y = -5$

$\sf Then,$

$\sf Coefficient \: of\: squared\: expression.\: in\: parabola's\: Eqn.$ :

$\sf y$ = $\sf a(x - h)^{2}$ + $\sf k$

⇒ $\sf a = \dfrac{\sf y - k}{\sf (x - h)^{2}}$

⇒ $\sf a = \dfrac{\sf -5 + 3}{\sf (-1 + 2)^{2}}$

⇒ $\sf a = \dfrac{\sf -2}{\sf 1}$

⇒ $\boxed{\sf a = \sf -2}$

$\sf Hence,$
$\sf Coefficient \: of\: squared\: expression.\: is\:D.\: -2$

~ $\sf iCarl$