Question

write a quadratic function f whose zeros are -10 and -2

Answer 1

$f(x) = (x - -10)(x - -2)$

We could stop here and have answered the question.

$f(x) = (x+10)(x+2) = x^2 + 12 x + 20$

Answer: $f(x)=x^2+12x + 20$

Answer 2

Hiiiiiiiiiiiiiiii mate......

here is your answer......✌✌✌✌

let alpha = -10 and beeta = -2
sum of zeroes= (alpha+beeta)=-10+-2=-12
product of zeroes= alpha.beeta= -10×-2=20
so,the required polynomial is

x^2-(alpha+beeta)X+alpha.beeta
x^2+12x+20

hope it help you...